Introduction to Elasticity

Example 1 Take a unit cube of material. Rotate it 90 degrees in the clockwise direction around the z-axis. Calculate the strains. Discuss your results - their accuracy and the reasons for your conclusions. Solution
The strains are related to displacements by
  \epsilon_{xx} = \frac{\partial u}{\partial x};~  \epsilon_{yy} = \frac{\partial v}{\partial y};~   \epsilon_{zz} = \frac{\partial w}{\partial z};~   \gamma_{xy} = \frac{\partial u}{\partial y} + \frac{\partial v}{\partial x};~  \gamma_{yz} = \frac{\partial v}{\partial z} + \frac{\partial w}{\partial y};~  \gamma_{zx} = \frac{\partial w}{\partial x} + \frac{\partial u}{\partial z}
Let us consider rotation about the center of the cube. Since the problem concerns a pure rotation, a cylindrical co-ordinate system is appropriate. This problem also provides us a easy way of trying out Maple. Here are the steps that you can follow to find the strains at a point in the cube.

r := sqrt(x^2+y^2);
r := \sqrt{x^{2} + y^{2}}

theta := arctan(y/x);
\theta  := arctan(\frac{y}{x})

x1 := r*cos(theta);
x1 := \frac{\sqrt{x^2 + y^2}}{\sqrt{1 + \frac{y^2}{x^2}}}

y1 := r*sin(theta);
y1 := \frac{\sqrt{x^2 + y^2}\,y}{x\,\sqrt{1 + \frac{y^2}{x^2}}}

x2 := r*cos(theta+Pi/2);
x2 :=  -\frac{\sqrt{x^2 + y^2}\,y}{x\,\sqrt{1 + \frac{y^2}{x^2}}}


gamxy: = 0
From the above Maple calculation, and noting that there is no motion in the z direction, the strains in the cube are
  \epsilon_{xx} = -1;~\epsilon_{yy} = -1; \epsilon_{zz} = 0;  \gamma_{xy} = 0; \gamma_{yz} = 0; \gamma_{zx} = 0
A pure rigid body rotation should not result in any non-zero strains.
Therefore, the measure of strain we have used is not appropriate for large rigid body motions.

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